增加采购申请对于单件制造非首个制造订单的显示,修改采购申请对于同一个补货组同一个产品的合并

This commit is contained in:
胡尧
2025-05-07 16:34:45 +08:00
parent fffbfc21c2
commit c24bba3137
2 changed files with 49 additions and 6 deletions

View File

@@ -1,4 +1,5 @@
from odoo import api, fields, models
from collections import defaultdict
class StockRule(models.Model):
@@ -44,7 +45,39 @@ class StockRule(models.Model):
purchase_request_line_model.create(request_line_data)
def _run_buy(self, procurements):
res = super(StockRule, self)._run_buy(procurements)
# 如果补货组相同,并且产品相同,则合并
procurements_dict = defaultdict()
for procurement, rule in procurements:
if (procurement.product_id, procurement.values['group_id'], rule) not in procurements_dict:
procurements_dict[(procurement.product_id, procurement.values['group_id'], rule)] = {
'product_id': procurement.product_id,
'product_qty': procurement.product_qty,
'product_uom': procurement.product_uom,
'location_id': procurement.location_id,
'name': procurement.name,
'origin': procurement.origin,
'company_id': procurement.company_id,
'values': procurement.values,
'rule': rule
}
else:
procurements_dict[(procurement.product_id, procurement.values['group_id'], rule)]['product_qty'] += procurement.product_qty
new_procurements = []
for k, p in procurements_dict.items():
new_procurements.append((
self.env['procurement.group'].Procurement(
product_id=p['product_id'],
product_qty=p['product_qty'],
product_uom=p['product_uom'],
location_id=p['location_id'],
name=p['name'],
origin=p['origin'],
company_id=p['company_id'],
values=p['values']
), p['rule'])
)
res = super(StockRule, self)._run_buy(new_procurements)
# 判断是否根据规则生成新的采购申请单据,如果生成则修改状态为 approved
origins = list(set([procurement[0].origin for procurement in procurements]))
for origin in origins: