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Accept Merge Request #1101: (feature/修复工单完成报错库存问题 -> develop)

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Merge Request: 修复制造订单生成时没有采购单

Created By: @杨金灵
Reviewed By: @马广威
Approved By: @马广威 
Accepted By: @杨金灵
URL: https://jikimo-hn.coding.net/p/jikimo_sfs/d/jikimo_sf/git/merge/1101?initial=true
This commit is contained in:
杨金灵
2024-06-26 16:40:40 +08:00
committed by Coding
parent f8ba414229 dbd5c488f8
commit 53c6d6015e
3 changed files with 34 additions and 31 deletions
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56
sf_manufacturing/models/stock.py
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@@ -205,39 +205,17 @@ class StockRule(models.Model):
productions_values)
# self.env['stock.move'].sudo().create(productions._get_moves_raw_values())
self.env['stock.move'].sudo().create(productions._get_moves_finished_values())
productions.filtered(lambda p: (not p.orderpoint_id and p.move_raw_ids) or \
(
p.move_dest_ids.procure_method != 'make_to_order' and not
p.move_raw_ids and not p.workorder_ids)).action_confirm()
'''
创建工单
'''
# productions._create_workorder()
#
grouped_product_ids = {k: list(g) for k, g in groupby(productions, key=lambda x: x.product_id.id)}
# 初始化一个字典来存储每个product_id对应的生产订单名称列表
product_id_to_production_names = {}
# 对于每个product_id，获取其所有生产订单的名称
for product_id, productions in grouped_product_ids.items():
# 为同一个product_id创建一个生产订单名称列表
product_id_to_production_names[product_id] = [production.name for production in productions]
for production_item in productions:
if production_item.product_id.id in product_id_to_production_names:
# # 同一个产品多个制造订单对应一个编程单和模型库
# # 只调用一次fetchCNC，并将所有生产订单的名称作为字符串传递
if not production_item.programming_no:
production_programming = self.env['mrp.production'].search(
[('product_id.id', '=', production_item.product_id.id),
('origin', '=', production_item.origin)],
limit=1, order='id asc')
if not production_programming.programming_no:
production_item.fetchCNC(
', '.join(product_id_to_production_names[production_item.product_id.id]))
else:
production_item.write({'programming_no': production_programming.programming_no,
'programming_state': '编程中'})
self.env['stock.move'].sudo().create(productions._get_moves_finished_values())
productions.filtered(lambda p: (not p.orderpoint_id and p.move_raw_ids) or \
(
p.move_dest_ids.procure_method != 'make_to_order' and not
p.move_raw_ids and not p.workorder_ids)).action_confirm()
for production in productions:
'''
创建制造订单时生成序列号
@@ -283,6 +261,28 @@ class StockRule(models.Model):
'product_id': production.product_id.id,
'state': 'draft',
})
grouped_product_ids = {k: list(g) for k, g in groupby(productions, key=lambda x: x.product_id.id)}
# 初始化一个字典来存储每个product_id对应的生产订单名称列表
product_id_to_production_names = {}
# 对于每个product_id，获取其所有生产订单的名称
for product_id, productions in grouped_product_ids.items():
# 为同一个product_id创建一个生产订单名称列表
product_id_to_production_names[product_id] = [production.name for production in productions]
for production_item in productions:
if production_item.product_id.id in product_id_to_production_names:
# # 同一个产品多个制造订单对应一个编程单和模型库
# # 只调用一次fetchCNC，并将所有生产订单的名称作为字符串传递
if not production_item.programming_no:
production_programming = self.env['mrp.production'].search(
[('product_id.id', '=', production_item.product_id.id),
('origin', '=', production_item.origin)],
limit=1, order='id asc')
if not production_programming.programming_no:
production_item.fetchCNC(
', '.join(product_id_to_production_names[production_item.product_id.id]))
else:
production_item.write({'programming_no': production_programming.programming_no,
'programming_state': '编程中'})
return True