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优化制造订单和生成工单逻辑

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jinling.yang
2024-06-19 17:35:13 +08:00
parent b390712308
commit 67b48814f6
6 changed files with 87 additions and 152 deletions
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30
sf_manufacturing/models/stock.py
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@@ -210,7 +210,7 @@ class StockRule(models.Model):
创建工单
'''
# productions._create_workorder()
根据product_id对self进行分组
# 根据product_id对self进行分组
grouped_product_ids = {k: list(g) for k, g in groupby(self, key=lambda x: x.productions.product_id.id)}
# 初始化一个字典来存储每个product_id对应的生产订单名称列表
product_id_to_production_names = {}
@@ -219,20 +219,20 @@ class StockRule(models.Model):
# 为同一个product_id创建一个生产订单名称列表
product_id_to_production_names[product_id] = [production.name for production in productions]
for production_item in productions:
if production_item.product_id.id in product_id_to_production_names:
# # 同一个产品多个制造订单对应一个编程单和模型库
# # 只调用一次fetchCNC，并将所有生产订单的名称作为字符串传递
if not production_item.programming_no:
production_programming = self.search(
[('product_id.id', '=', production_item.product_id.id),
('origin', '=', production_item.origin)],
limit=1, order='id asc')
if not production_programming.programming_no:
production_item.fetchCNC(
', '.join(product_id_to_production_names[production_item.product_id.id]))
else:
production_item.write({'programming_no': production_programming.programming_no,
'programming_state': '编程中'})
# if production_item.product_id.id in product_id_to_production_names:
# # 同一个产品多个制造订单对应一个编程单和模型库
# # 只调用一次fetchCNC，并将所有生产订单的名称作为字符串传递
if not production_item.programming_no:
production_programming = self.env['mrp.production'].search(
[('product_id.id', '=', production_item.product_id.id),
('origin', '=', production_item.origin)],
limit=1, order='id asc')
if not production_programming.programming_no:
production_item.fetchCNC(
', '.join(product_id_to_production_names[production_item.product_id.id]))
else:
production_item.write({'programming_no': production_programming.programming_no,
'programming_state': '编程中'})
productions.filtered(lambda p: (not p.orderpoint_id and p.move_raw_ids) or \
(