Accept Merge Request #1654: (feature/part_number -> develop)

Merge Request: 两张外协工单报错问题

Created By: @廖丹龙
Reviewed By: @胡尧
Approved By: @胡尧 
Accepted By: @廖丹龙
URL: https://jikimo-hn.coding.net/p/jikimo_sfs/d/jikimo_sf/git/merge/1654
This commit is contained in:
廖丹龙
2024-12-27 17:08:40 +08:00
committed by Coding
2 changed files with 38 additions and 39 deletions

View File

@@ -803,45 +803,45 @@ class MrpProduction(models.Model):
workorder.move_subcontract_workorder_ids.picking_id.write({'state': 'cancel'})
consecutive_workorders = []
sorted_workorders = sorted(process_parameter_workorder, key=lambda w: w.sequence)
for i, workorder in enumerate(sorted_workorders):
# 检查当前工作订单和下一个工作订单是否连续,并且供应商相同
if i == 0:
consecutive_workorders.append(workorder)
elif workorder.sequence == sorted_workorders[
i - 1].sequence + 1 and workorder.supplier_id.id == sorted_workorders[i - 1].supplier_id.id:
consecutive_workorders.append(workorder)
else:
# 处理连续组,如果它不为空
if consecutive_workorders:
proc_workorders.append(consecutive_workorders)
# 创建外协出入库单和采购订单
# self.env['stock.picking'].create_outcontract_picking(consecutive_workorders, production, sorted_workorders)
# self.env['purchase.order'].get_purchase_order(consecutive_workorders, production,
# product_id_to_production_names)
if i < len(sorted_workorders) - 1:
# 重置连续组,并添加当前工作订单
consecutive_workorders = [workorder]
else:
# 判断最后一笔:
if workorder.sequence == sorted_workorders[
i - 1].sequence and workorder.supplier_id.id == sorted_workorders[
i - 1].supplier_id.id:
consecutive_workorders = [workorder]
else:
proc_workorders.append([workorder])
# 立即创建外协出入库单和采购订单
# self.env['stock.picking'].create_outcontract_picking(workorder, production)
# self.env['purchase.order'].get_purchase_order(workorder, production,
# product_id_to_production_names)
consecutive_workorders = []
# 处理最后一个组,即使它可能只有一个工作订单
if consecutive_workorders:
proc_workorders.append(consecutive_workorders)
# for i, workorder in enumerate(sorted_workorders):
# # 检查当前工作订单和下一个工作订单是否连续,并且供应商相同
# if i == 0:
# consecutive_workorders.append(workorder)
# elif workorder.sequence == sorted_workorders[
# i - 1].sequence + 1 and workorder.supplier_id.id == sorted_workorders[i - 1].supplier_id.id:
# consecutive_workorders.append(workorder)
# else:
# # 处理连续组,如果它不为空
# if consecutive_workorders:
# proc_workorders.append(consecutive_workorders)
# # 创建外协出入库单和采购订单
# # self.env['stock.picking'].create_outcontract_picking(consecutive_workorders, production, sorted_workorders)
# # self.env['purchase.order'].get_purchase_order(consecutive_workorders, production,
# # product_id_to_production_names)
# if i < len(sorted_workorders) - 1:
# # 重置连续组,并添加当前工作订单
# consecutive_workorders = [workorder]
# else:
# # 判断最后一笔:
# if workorder.sequence == sorted_workorders[
# i - 1].sequence and workorder.supplier_id.id == sorted_workorders[
# i - 1].supplier_id.id:
# consecutive_workorders = [workorder]
# else:
# proc_workorders.append([workorder])
# # 立即创建外协出入库单和采购订单
# # self.env['stock.picking'].create_outcontract_picking(workorder, production)
# # self.env['purchase.order'].get_purchase_order(workorder, production,
# # product_id_to_production_names)
# consecutive_workorders = []
#
# # 处理最后一个组,即使它可能只有一个工作订单
# if consecutive_workorders:
# proc_workorders.append(consecutive_workorders)
# self.env['stock.picking'].create_outcontract_picking(consecutive_workorders, production)
# self.env['purchase.order'].get_purchase_order(consecutive_workorders, production,
# product_id_to_production_names)
for workorders in reversed(proc_workorders):
for workorders in reversed(sorted_workorders):
self.env['stock.picking'].create_outcontract_picking(workorders, production, sorted_workorders)
self.env['purchase.order'].get_purchase_order(workorders, production, product_id_to_production_names)