46 lines
2.3 KiB
Python
46 lines
2.3 KiB
Python
from itertools import groupby
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from odoo import models, api
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from odoo.tools.misc import OrderedSet
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class MrpProduction(models.Model):
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_inherit = 'mrp.production'
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@api.model_create_multi
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def create(self, vals_list):
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"""
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生成编程单
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"""
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productions = super().create(vals_list)
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if not productions:
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return self.browse()
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# 定义变量存储编程单
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grouped_product_programming_no = {}
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# 定义产品拼接成的制造订单名称
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grouped_product_production_name = {}
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# 查出所有的制造订单，为了适配通过补货生成的制造订单
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all_productions = self.env['mrp.production'].search([('origin', '=', productions[0].origin)])
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# 将不同产品的制造订单进行分组
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grouped_product_productions = {k: list(g) for k, g in groupby(all_productions, key=lambda x: x.product_id.id)}
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for product_id, grouped_productions in grouped_product_productions.items():
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# 产品对应的编程单号
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if product_id not in grouped_product_programming_no:
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# 使用列表推导式获取非空的programming_no
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programming_nos = [p.programming_no for p in grouped_productions if p.programming_no if p.programming_no is not False]
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if programming_nos:
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grouped_product_programming_no[product_id] = programming_nos[0]
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grouped_product_production_name[product_id] = ','.join(list(map(lambda p:p.name, grouped_productions)))
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# 同一个产品的制造订单只请求一次CNC编程
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for production in productions:
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if not production.programming_no and production.production_type in ['自动化产线加工','人工线下加工']:
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if production.product_id.id not in grouped_product_programming_no:
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production.fetchCNC(grouped_product_production_name[production.product_id.id])
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grouped_product_programming_no[production.product_id.id] = production.programming_no
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else:
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production.write({
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'programming_no': grouped_product_programming_no[production.product_id.id],
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'programming_state': '编程中'
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})
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return productions |